Feb 8th 2021 #1 Hello, make it sense to leave the VDD pin of the protection circuit open? How will the positive overvoltage discharge without breaking one of the diodes? In my opinion the circuit should be something like this. Thank you for reply. Best regards, Daniel
Feb 9th 2021 #2 Hello, you are right! Normally we connect pin 5 to USB-VBUS and leave pin 1 open. This is a mistake. Thank you for the hint! Best regards, Torsten